Saturday, 10 October 2015

Am I calculating this right? 25600mAh Power bank Capacity test



Hi,

I have recently bought a Li-Polymer power bank which has a rated capacity of 25600 mAh @ 3.7V or 94720mWh. Now, I have been testing this power bank using a 1A and 2A load. Here are the readings I got whilst charging and discharging the power bank.:

All readings are at 5V. The powerbank was charged at 2A and discharged at 2A or 1A USB resistor load.

and this was used to record mAh


Here's the readings:
Charge: 24897mAh
Discharge: 16985mAh @ 2a discharge

Charge: 24814mAh
Discharge: 15020mAh @ 2a discharge

Charge: 24787mAh
Discharge= 16759 @ 1a discharge

Charge: 24750mAh
Discharge = Yet to do

Lets take example 1 from the list above:
Charge
24897 x 5 = 124485mWh
There was a conversion from 5V input to 3.7 output, with an efficiency of 80%
124485 x 0.8 = 99588mWh
So 99588mWh or 26915mAh @ 3.7V should be the power bank capacity

Discharge using 2A load
16985 x 5 = 84925mWh
84925 is the capacity after efficiency loss (20%) from the circuit. So power output before conversion and loss will be:
84925 x 1.2 = 101910mWh
101910 or 27543 @3.7V

So the power bank's capacity in the above example is around 27000mAh. Just wanted to make sure that my calculations were ok.



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